🔤 Sequences and the nth term
Patterns are everywhere: seats in a stadium, tiles on a floor, the price of a taxi ride as the kilometres tick up. If you can find the rule behind a pattern, you can jump straight to the 100th step without drawing the 99 before it. That rule is called the nth term, and it is one of the most powerful ideas in algebra.
- I can continue a sequence and describe its term-to-term rule.
- I can find and use the nth term of a linear sequence in the form an + b.
- I can decide whether a number is in a sequence.
- I can find sequences from patterns and real-life situations.
- I can recognise square numbers and simple sequences based on n².
- sequence
- a list of numbers in order that follows a rule
- term
- each number in a sequence
- position (n)
- where a term is in the sequence: 1st, 2nd, 3rd, …
- term-to-term rule
- how to get from one term to the next, such as “add 3”
- nth term
- a rule that gives any term from its position n, such as 3n + 2
- linear sequence
- a sequence that goes up or down by the same amount each time
- difference
- the amount added (or subtracted) each time
- square numbers
- 1, 4, 9, 16, …: the numbers n²
1 Learn it
Patterns make sequences
Look at these matchstick squares. Each new square needs 3 more matches, because it shares one side with the square before.
So the numbers of matches make the sequence 4, 7, 10, 13, … Each number is a term. The term-to-term rule is “add 3”.
Position-to-term: the nth term
Put the terms in a table with their position n.
The sequence 5, 8, 11, 14 goes up in 3s, just like the 3 times table (3, 6, 9, 12). Each term is 2 more than the 3 times table.
So each term is 3 × n + 2. We write the nth term as 3n + 2.
| Position n | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| 3n | 3 | 6 | 9 | 12 |
| Term | 5 | 8 | 11 | 14 |
Finding the nth term quickly
Step 1: find the difference, a. The nth term starts with an.
Step 2: step back one place from the first term to find the zero term, b. The nth term is an + b.
For 7, 11, 15, 19: the difference is 4, and stepping back from 7 gives 7 − 4 = 3.
- Difference: 4, so start with 4n
- Zero term: \(7 – 4 = 3\)
- nth term \(= 4n + 3\)
- Check n = 2: 4 × 2 + 3 = 11 ✓
Using the nth term
To find any term, put its position in place of n.
To test whether a number is in the sequence, set the nth term equal to it and solve. If n comes out as a whole number, the number is in the sequence. If not, it is not.
- 50th term of \(4n + 3\): 4 × 50 + 3 = 203
- Is 95 in \(4n + 3\)? Solve 4n + 3 = 95
- \(4n = 92\), so \(n = 23\): yes, the 23rd term
- Is 100 in \(4n + 3\)? \(4n = 97\), so n = 24.25: no
Sequences in real life
Tables in a restaurant are pushed together in a row. Each extra table adds 2 more chairs, one on each long side.
Real-life rules are often linear: a fixed start-up amount plus the same amount for each step. A taxi that charges P15 to start and P6 per kilometre costs 6n + 15 pula for n km.
Square numbers: a sequence that is not linear
Square numbers come from square patterns of dots: 1, 4, 9, 16, 25, … The nth term is \(n^2\).
The differences are 3, 5, 7, 9, …, so they are not the same each time. This is not a linear sequence.
Many sequences are built from n²: for example \(n^2 + 1\) gives 2, 5, 10, 17, … and \(2n^2\) gives 2, 8, 18, 32, …
2 Watch it work
Find and use the nth term
- (a) Difference: \(11 – 7 = 4\), so start with 4n
- Zero term: \(7 – 4 = 3\)
- nth term \(= 4n + 3\)
- (b) \(4 \times 20 + 3\)
- \(= 83\)
A decreasing sequence
- (a) Difference: 17 − 20 = −3, so start with −3n
- Zero term: \(20 + 3 = 23\)
- nth term \(= 23 – 3n\)
- (b) Solve 23 − 3n = −10
- \(33 = 3n\)
- \(n = 11\), a whole number
Is the number in the sequence?
- Solve 3n + 2 = 100
- \(3n = 98\)
- n = 32.66…
- n is not a whole number
- Check: the 32nd term is 98 and the 33rd term is 101
A matchstick pattern
- (a) Difference 3, zero term 4 − 3 = 1, so 3n + 1
- (b) 3 × 30 + 1 = 91
- (c) Solve 3n + 1 = 200
- \(3n = 199\), so n = 66.33…
- 66 squares use 3 × 66 + 1 = 199 matches; 67 squares would need 202
A sequence built on square numbers
- Differences: 3, 5, 7, 9, which are not equal, so it is not linear
- Compare with the square numbers: 1, 4, 9, 16, 25
- Each term is 1 more than a square number
- nth term \(= n^2 + 1\)
- 10th term: \(10^2 + 1 = 101\)
3 Your turn
Try each question in your book first. Then tap the button to check every step.
👀 Show the answer
- The terms go up by 5 each time
- \(21 + 5 = 26\)
- \(26 + 5 = 31\)
👀 Show the answer
- n = 1: \(2 + 5 = 7\)
- n = 2: \(4 + 5 = 9\)
- n = 3: \(6 + 5 = 11\)
- n = 4: \(8 + 5 = 13\)
👀 Show the answer
- These are the multiples of 4
- Difference 4 and zero term 0
👀 Show the answer
- \(1^2, 2^2, 3^2, 4^2, 5^2\)
- 1, 4, 9, 16, 25
- \(12^2 = 144\)
👀 Show the answer
- Difference: 6, so start with 6n
- Zero term: \(9 – 6 = 3\)
👀 Show the answer
- Difference: −4, so start with −4n
- Zero term: \(50 + 4 = 54\)
👀 Show the answer
- The terms go up by \(\dfrac{1}{2}\) each time, so start with \(\dfrac{1}{2}n\)
- Zero term: \(\dfrac{1}{2} – \dfrac{1}{2} = 0\)
- nth term \(= \dfrac{1}{2}n\), which is the same as \(\dfrac{n}{2}\)
- 20th term: \(\dfrac{20}{2} = 10\)
👀 Show the answer
- \(7 \times 100 – 3\)
- \(= 697\)
👀 Show the answer
- (a) \(4n + 3 = 75\), so \(4n = 72\)
- \(n = 18\), a whole number: yes
- (b) 6n + 5 = 150, so \(6n = 145\)
- n = 24.16…, not a whole number: no
👀 Show the answer
- (a) Each km adds P6, and P15 is fixed
- Cost \(= 6n + 15\)
- (b) \(6 \times 12 + 15\)
- \(= 87\)
👀 Show the answer
- Chairs: 4, 6, 8, … so the difference is 2
- Zero term: \(4 – 2 = 2\)
- (a) nth term \(= 2n + 2\)
- (b) 2 × 20 + 2 = 42
👀 Show the answer
- From the 3rd term to the 7th term is 4 steps
- The terms went up by 37 − 17 = 20
- Difference: \(20 \div 4 = 5\)
- 1st term: 17 − 2 × 5 = 7
- Zero term: \(7 – 5 = 2\)
- nth term \(= 5n + 2\)
👀 Show the answer
- Solve 3n + 4 = 500
- \(3n = 496\), so n = 165.33…
- So the 165th term is just below 500
- The 166th term: 3 × 166 + 4 = 502
👀 Show the answer
- Differences: 3, 5, 7, 9, not equal, so not linear
- Square numbers: 1, 4, 9, 16, 25
- Each term is 2 more than a square number
- nth term \(= n^2 + 2\)
- 10th term: \(10^2 + 2 = 102\)
👀 Show the answer
- Set them equal: 5n + 1 = 3n + 11
- \(2n = 10\)
- \(n = 5\)
- Term: 5 × 5 + 1 = 26
- Check: 3 × 5 + 11 = 26 ✓
4 Watch out!
The difference goes in FRONT of n: “up in 4s” means 4n. Then adjust: 4n gives 4, 8, 12, …, which is 1 too big, so 4n − 1.
“+3” only tells you the next term. The nth term must give any term from its position n.
The sequence goes DOWN by 3, so the difference is −3. Check n = 1: 23 − 3 = 20 ✓, but 3 + 23 = 26 ✗.
Positions are whole numbers. The 32nd term is 98 and the 33rd is 101; 100 is skipped.
5 In your exams
In JCE Paper 1, sequences usually appear as multiple choice: the next term, a missing term, or which expression is the nth term. In Paper 2 (often Section B or C), you meet a pattern of matchsticks, dots or tiles: you complete a table, find the nth term, use it for a large pattern number, and decide whether a given number of sticks is possible. Always check your nth term with the first two terms.
IGCSE 0580 Core asks for the nth term of linear sequences and simple ones based on n², often from a diagram pattern. Extended papers go further: quadratic and cubic sequences, exponential sequences such as \(2^n\), and sequences with fractions.
👀 Reveal the solution
- Grey tiles: 8, 12, 16, … so difference 4 and zero term 8 − 4 = 4
- (a) Grey tiles \(= 4n + 4\)
- The whole pattern is a square with side n + 2
- (b) Total tiles \(= (n + 2)^2\)
- (c) \((n + 2)^2 = 144\), so n + 2 = 12
- \(n = 10\)
- Grey: 4 × 10 + 4 = 44
- Check: \(100\) white \(+ 44\) grey = 144 ✓
- The term-to-term rule gives the next term; the nth term gives ANY term from its position n.
- Linear sequence nth term = an + b: a is the difference, b is the zero term (one step before the 1st term).
- Decreasing sequences have a negative difference, e.g. 23 − 3n.
- A number is in the sequence only if solving an + b = number gives a whole-number n.
- If the differences are not equal, compare with the square numbers 1, 4, 9, 16, 25 (nth term n²).