Pythagoras’ Theorem
Anchors: legs 6 and 8 → hyp = √(36 + 64) = 10. Hyp 13, one leg 5 → other = √(169 − 25) = 12.
Real-life disguises: the diagonal of a rectangle, a ladder against a wall, the distance between two coordinate points (CG-E2 was Pythagoras all along!). Answers may be surds when “exact” is demanded.
Legs 6 cm and 8 cm. Find the hypotenuse.
c = √(36 + 64) = √100 = 10 cm
Hypotenuse 13 cm, one leg 5 cm. Find the other leg.
√(169 − 25) = √144 = 12 cm — SUBTRACT when hunting a leg.
Find the diagonal of an 8 cm × 6 cm rectangle.
√(64 + 36) = 10 cm — the rectangle hides a right triangle.
A 5 m ladder leans against a wall, foot 1.4 m out. How high does it reach? 🔢
√(25 − 1.96) = √23.04 = 4.8 m — ladder = hypotenuse, so subtract.
Q1. Legs 9 cm and 12 cm. Find the hypotenuse.
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Q2. Hypotenuse 17 cm, one leg 8 cm. Find the other leg.
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Q3. A rectangle is 7.5 m by 4 m. Find its diagonal (3 s.f.).
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d = 8.50 m ✓ A1
Q4. A 6 m ladder rests with its top 5.5 m up a wall. How far is its foot from the wall (3 s.f.)?
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x = 2.40 m ✓ A1
Q5. Find the EXACT hypotenuse of a triangle with legs 2 cm and 6 cm.
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- Adding when the hypotenuse is GIVEN: hunting a leg means subtracting.
- Forgetting the final root: 225 is c², not c.
- Using Pythagoras without a right angle: it only works in right triangles (T-E4 handles the rest).
- Rounding early in two-step problems.
Pythagoras earns direct marks and hides inside cones (M-C4), coordinate lengths (CG-E2) and 3-D work (T-E5). Next: SOHCAHTOA — when the angle joins the party.