Single Events & the Complement Rule
All the probabilities of every possible outcome of an experiment add to 1. That gives you missing values for free: if a spinner lands red, blue or green with P(red) = 0.35 and P(blue) = 0.4, then P(green) = 1 − 0.35 − 0.4 = 0.25.
Watch the wording: “a card is chosen at random” means every card is equally likely — that phrase is your licence to count outcomes.
The probability that a bus is late is 0.15. Find P(not late).
1 − 0.15 = 0.85.
A spinner lands on red, blue or green. P(red) = 0.35, P(blue) = 0.4. Find P(green).
1 − 0.35 − 0.4 = 0.25.
The letters of the word KALAHARI are written on cards and one is picked at random. Find P(A) and P(not A).
KALAHARI has 8 letters with three A’s → P(A) = \(\dfrac{3}{8}\); P(not A) = 1 − \(\dfrac{3}{8}\) = \(\dfrac{5}{8}\).
A box holds only 2-pula and 5-pula coins. A coin is taken at random; P(5-pula) = \(\dfrac{7}{12}\). There are 36 coins. How many are 2-pula?
P(2-pula) = 1 − \(\dfrac{7}{12}\) = \(\dfrac{5}{12}\); \(\dfrac{5}{12}\) × 36 = 15 coins.
Q1. P(a seed grows) = 0.7. Find P(the seed does not grow).
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Q2. A spinner lands on 1, 2, 3 or 4. P(1) = 0.2, P(2) = 0.3, P(3) = 0.1. Find P(4).
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P(4) = 1 − 0.6 = 0.4 ✓ A1
Q3. One letter of GABORONE is picked at random. Find P(O) and P(not O).
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P(not O) = 34 ✓ B1
Q4. A drawer holds only black and white socks. A sock is taken at random; P(black) = \(\dfrac{5}{9}\). There are 45 socks. How many are white?
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49 × 45 ✓ M1
= 20 socks ✓ A1
Q5. P(a team wins) = 0.55 and P(the match is drawn) = 0.2. Find P(the team loses).
👀 Show answer
= 0.25 ✓ A1
- Subtracting from 100 instead of 1 when working in decimals (0.7 → 0.3, not 99.3).
- Forgetting repeated letters: KALAHARI has THREE A’s, not one.
- Complement of a fraction done wrong: 1 − \(\dfrac{5}{9}\) = \(\dfrac{4}{9}\), not \(\dfrac{5}{9}\) flipped.
- Not simplifying when the answer line asks for simplest form.
Missing-probability tables are a guaranteed 2-marker. Next: what happens when you actually run the experiment — relative frequency in P-C2.