Module 22 of 30Lesson 1 of 36 · N-E0a Types of Number, Powers, Roots and Ordering at Extended Level
Number strand · Unit N-E0a · Syllabus E1.1, E1.3, E1.5

Types of Number, Powers, Roots and Ordering at Extended Level

🟠 Extended level
Primes, HCF/LCM, rational vs irrational, roots, ordering

1 Learn it

Quick recap of the families. Natural numbers are 1, 2, 3, … Integers add 0 and the negatives. A prime has exactly two factors (so 1 is NOT prime). You should also recognise square numbers (1, 4, 9, 16, …), cube numbers (1, 8, 27, 64, …) and triangle numbers (1, 3, 6, 10, 15, …).

Prime factorisation writes a number as a product of primes in index form: \(360 = 2^{3} \times 3^{2} \times 5\). At Extended level you use it to find the HCF and LCM of two or three numbers at once:

🔑 Write each number as a product of primes. HCF = multiply the primes that appear in ALL the numbers, using the lowest power of each. LCM = multiply EVERY prime that appears anywhere, using the highest power of each.

Rational or irrational? A number is rational if it can be written as \(\dfrac{a}{b}\) with \(a\) and \(b\) integers (\(b \neq 0\)). That includes integers, terminating decimals and recurring decimals — for example \(0.\dot{2}\dot{7} = \dfrac{27}{99} = \dfrac{3}{11}\). A number is irrational if its decimal goes on forever with no repeating pattern: \(\pi\), and surds such as \(\sqrt{2}\), \(\sqrt{12}\) and \(\sqrt[3]{10}\). Careful: \(\sqrt{2.25} = 1.5\) and \(\sqrt{\dfrac{9}{4}} = \dfrac{3}{2}\) look like surds but are rational.

Reciprocals. The reciprocal of \(x\) is \(\dfrac{1}{x}\). Turn a mixed number into an improper fraction first, then flip: reciprocal of \(1\dfrac{3}{5} = \dfrac{8}{5}\) is \(\dfrac{5}{8}\). For a decimal, write it as a fraction: \(0.4 = \dfrac{2}{5}\), so its reciprocal is \(\dfrac{5}{2} = 2.5\).

Powers and roots of fractions and decimals. Apply the power or root to the top AND the bottom: \(\left(\dfrac{2}{3}\right)^{3} = \dfrac{8}{27}\), \(\sqrt{0.0081} = 0.09\) (because \(0.09^{2} = 0.0081\)), \(\sqrt[3]{-0.125} = -0.5\). Cube roots of negatives exist; square roots of negatives do not (in IGCSE).

Ordering. To order a mixed list (fractions, decimals, percentages, roots, standard form, negatives), change everything to decimals with the same number of places, then compare. Use the symbols \(=\), \(\neq\), \(<\), \(>\), \(\leq\), \(\geq\) correctly: \(x \leq 2\) includes 2; \(x < 2\) does not.

2 Watch it work
EXAMPLE 1

Find the HCF and the LCM of 84, 120 and 180.

\(84 = 2^{2} \times 3 \times 7\)    \(120 = 2^{3} \times 3 \times 5\)    \(180 = 2^{2} \times 3^{2} \times 5\)

HCF: only 2 and 3 are in all three. Lowest powers: \(2^{2} \times 3 = 12\).

LCM: every prime (2, 3, 5, 7), highest powers: \(2^{3} \times 3^{2} \times 5 \times 7 = 2520\).

EXAMPLE 2

Three combis leave the Gaborone bus rank together at 06:00. Route A leaves every 12 minutes, route B every 18 minutes and route C every 30 minutes. When do all three next leave together?

“Next time together” means the LCM.

\(12 = 2^{2} \times 3\),   \(18 = 2 \times 3^{2}\),   \(30 = 2 \times 3 \times 5\)   ⇒   LCM \(= 2^{2} \times 3^{2} \times 5 = 180\) minutes

180 minutes = 3 hours, so they next leave together at 09:00.

EXAMPLE 3

Without a calculator: (a) write down the reciprocal of \(1\dfrac{3}{5}\) and of 0.4; (b) evaluate \(\left(\dfrac{2}{3}\right)^{3}\), \(\sqrt{0.0081}\) and \(\left(1\dfrac{1}{2}\right)^{2}\).

(a) \(1\dfrac{3}{5} = \dfrac{8}{5}\) → reciprocal \(\dfrac{5}{8}\).   \(0.4 = \dfrac{2}{5}\) → reciprocal \(\dfrac{5}{2} = 2.5\).

(b) \(\left(\dfrac{2}{3}\right)^{3} = \dfrac{2^{3}}{3^{3}} = \dfrac{8}{27}\).   \(\sqrt{0.0081} = 0.09\).   \(\left(1\dfrac{1}{2}\right)^{2} = \left(\dfrac{3}{2}\right)^{2} = \dfrac{9}{4} = 2\dfrac{1}{4}\) (not \(1\dfrac{1}{4}\)!).

EXAMPLE 4

Write these in order, smallest first:   \(\dfrac{5}{8}\),   \(0.\dot{6}\),   62%,   \(\sqrt{0.4}\),   0.6

Convert to 4 decimal places: \(\dfrac{5}{8} = 0.6250\), \(0.\dot{6} = 0.6667\), 62% = 0.6200, \(\sqrt{0.4} = 0.6325\) (it lies between 0.63 and 0.64, since \(0.63^{2} = 0.3969\) and \(0.64^{2} = 0.4096\)), 0.6 = 0.6000.

\(0.6 < 62\% < \dfrac{5}{8} < \sqrt{0.4} < 0.\dot{6}\)

EXAMPLE 5

Show that \(0.\dot{2}\dot{7}\) is rational, and say whether \(\sqrt{12}\) is rational or irrational.

Let \(x = 0.272727\ldots\). Then \(100x = 27.2727\ldots\). Subtract: \(99x = 27\), so \(x = \dfrac{27}{99} = \dfrac{3}{11}\). It is a fraction of integers, so it is rational.

\(\sqrt{12} = 2\sqrt{3}\). 12 is not a square number, so \(\sqrt{12}\) is a surd: irrational.

3 Your turn — try first, then reveal
🚫 No calculator[2 marks]

Q1. Write 360 as a product of its prime factors. Give your answer in index form.

👀 Show answer
✍️ How your working should look in the exam
360 = 2 × 180 = 2 × 2 × 90 = 2 × 2 × 2 × 45 = 2 × 2 × 2 × 3 × 3 × 5   ✓ M1
= 23 × 32 × 5   ✓ A1
Why this works
Keep dividing by the smallest prime that works (2, then 3, then 5) until you reach 1. “Index form” means you must write \(2^{3}\), not \(2 \times 2 \times 2\), for the final mark.

🚫 No calculator[3 marks]

Q2. Find (a) the highest common factor (HCF) and (b) the lowest common multiple (LCM) of 72, 108 and 180.

👀 Show answer
✍️ How your working should look in the exam
72 = 23 × 32   108 = 22 × 33   180 = 22 × 32 × 5   ✓ M1
(a) HCF = 22 × 32 = 36   ✓ A1
(b) LCM = 23 × 33 × 5 = 1080   ✓ A1
Why this works
HCF: 2 and 3 are in all three; lowest powers are \(2^{2}\) and \(3^{2}\). The 5 is left out because 72 and 108 do not have it. LCM: take every prime with its highest power — \(2^{3}\) from 72, \(3^{3}\) from 108 and 5 from 180.

🚫 No calculator[2 marks]

Q3. \(A = 2^{4} \times 3 \times 5^{2}\) and \(B = 2^{2} \times 3^{3} \times 7\). Find the HCF of \(A\) and \(B\), and write the LCM of \(A\) and \(B\) in index form.

👀 Show answer
✍️ How your working should look in the exam
HCF = 22 × 3 = 12   ✓ B1
LCM = 24 × 33 × 52 × 7   ✓ B1
Why this works
The numbers are already factorised, so you never need to multiply out \(A\) and \(B\). Common primes are 2 and 3 (lowest powers \(2^{2}\) and \(3^{1}\)). For the LCM, all four primes appear, each with its highest power. (It equals 75 600, but index form is what was asked.)

🚫 No calculator[3 marks]

Q4. A rectangular floor in a Maun lodge measures 3.6 m by 4.8 m. It is covered with identical square tiles, with no cutting. Find the side length of the largest tile that can be used, and the number of these tiles needed.

👀 Show answer
✍️ How your working should look in the exam
360 cm = 23 × 32 × 5   480 cm = 25 × 3 × 5   ✓ M1
HCF = 23 × 3 × 5 = 120 cm   ✓ A1
360 ÷ 120 = 3,   480 ÷ 120 = 4,   3 × 4 = 12 tiles   ✓ A1
Why this works
The tile side must divide BOTH lengths exactly, and you want the biggest such number — that is the HCF. Change metres to centimetres first so you work with whole numbers. The tiles form a grid 3 tiles by 4 tiles.

🚫 No calculator[2 marks]

Q5. From this list, write down all the irrational numbers.

\(\sqrt{16}\)    \(\sqrt{20}\)    \(0.\dot{4}\)    \(\pi + 1\)    \(\dfrac{3}{7}\)    \(\sqrt{2.25}\)    \(\sqrt[3]{10}\)

👀 Show answer
✍️ How your working should look in the exam
√20,   π + 1,   ∛10   ✓✓ B2
(B1 for two correct and none wrong, or three correct and one wrong)
Why this works
\(\sqrt{16} = 4\), \(0.\dot{4} = \dfrac{4}{9}\), \(\dfrac{3}{7}\) and \(\sqrt{2.25} = 1.5\) are all rational. 20 is not a square and 10 is not a cube, so their roots never repeat. Adding 1 to \(\pi\) does not make it rational.

🚫 No calculator[2 marks]

Q6. Write down the reciprocal of (a) \(2\dfrac{3}{4}\)   (b) 0.08

👀 Show answer
✍️ How your working should look in the exam
(a) 234 = 114 → 411   ✓ B1
(b) 0.08 = 8100 → 1008 = 12.5   ✓ B1
Why this works
Reciprocal of a mixed number: make it improper, then flip. \(2\dfrac{4}{3}\) is a common wrong answer. Check (b): \(0.08 \times 12.5 = 1\) ✔ — a number times its reciprocal is always 1.

🚫 No calculator[3 marks]

Q7. Evaluate (a) \(\sqrt[3]{-\dfrac{64}{125}}\)   (b) \(0.3^{3}\)   (c) \(\sqrt{1\dfrac{9}{16}}\)

👀 Show answer
✍️ How your working should look in the exam
(a) −45   ✓ B1
(b) 0.3 × 0.3 × 0.3 = 0.027   ✓ B1
(c) √2516 = 54   ✓ B1
Why this works
(a) Cube root top and bottom: \(4^{3} = 64\), \(5^{3} = 125\), and a cube root of a negative is negative. (b) \(3^{3} = 27\) and three decimal places in total, so 0.027 — not 0.09 or 0.9. (c) Convert first: \(1\dfrac{9}{16} = \dfrac{25}{16}\). Rooting the parts separately (\(1 + \dfrac{3}{4}\)) is wrong.

🔢 Calculator[2 marks]

Q8. Work out \(\sqrt[4]{1296} + 2.5^{3}\).

👀 Show answer
✍️ How your working should look in the exam
⁴√1296 = 6,   2.53 = 15.625   ✓ M1
6 + 15.625 = 21.625   ✓ A1
Why this works
Use the \(\sqrt[x]{\ }\) key (or \(1296^{0.25}\)) for the fourth root and the \(x^{\blacksquare}\) key for the power. The answer is exact, so give all the digits — do not round.

🔢 Calculator[2 marks]

Q9. Write these numbers in order of size, starting with the smallest.

\(3.1 \times 10^{-2}\)    0.0302    \(\dfrac{1}{32}\)    0.3%

👀 Show answer
✍️ How your working should look in the exam
0.031,   0.0302,   0.03125,   0.003   ✓ M1
0.3%,   0.0302,   3.1 × 10−2,   132   ✓ A1
Why this works
Turn each into a decimal: \(3.1 \times 10^{-2} = 0.031\), \(\dfrac{1}{32} = 0.03125\), 0.3% = 0.003. Pad to 5 decimal places to compare: 0.00300, 0.03020, 0.03100, 0.03125. Then write the answer using the ORIGINAL forms.

🚫 No calculator[3 marks]

Q10. Write one of the symbols \(=\), \(<\) or \(>\) in each box.

(a) \(\sqrt{50}\ \square\ 7\)     (b) \((-2)^{3}\ \square\ -2^{3}\)     (c) \(\dfrac{3}{11}\ \square\ 0.27\)

👀 Show answer
✍️ How your working should look in the exam
(a) 72 = 49 < 50 so √50 > 7   ✓ B1
(b) −8 and −8 so (−2)3 = −23   ✓ B1
(c) 311 = 0.272727… > 0.27   ✓ B1
Why this works
(a) Square both sides to compare without a calculator. (b) An odd power keeps the minus sign, so both give −8. (With an even power, \((-2)^{4} = 16\) but \(-2^{4} = -16\).) (c) \(\dfrac{3}{11} = 0.\dot{2}\dot{7}\), which is just bigger than 0.27.

🚫 No calculator[2 marks]

Q11. \(n\) is an integer and \(-3 < n \leq 2\). List all the possible values of \(n\). Which of them are prime?

👀 Show answer
✍️ How your working should look in the exam
−2, −1, 0, 1, 2   ✓ B1
prime: 2 only   ✓ B1
Why this works
\(<\) at −3 means −3 is NOT included; \(\leq\) at 2 means 2 IS included. Primes are positive with exactly two factors, so 1, 0 and negatives are not prime — only 2.

4 Common mistakes — don’t lose easy marks
  • Mixing up HCF and LCM powers: HCF takes the LOWEST power of the shared primes; LCM takes the HIGHEST power of every prime.
  • Calling recurring decimals irrational: \(0.\dot{3} = \dfrac{1}{3}\) is rational. Only non-repeating, never-ending decimals (π, surds) are irrational.
  • Flipping a mixed number without converting: the reciprocal of \(2\dfrac{3}{4}\) is \(\dfrac{4}{11}\), not \(2\dfrac{4}{3}\).
  • Splitting a root over addition: \(\sqrt{1\dfrac{9}{16}} \neq 1\dfrac{3}{4}\). Make one fraction first: \(\sqrt{\dfrac{25}{16}} = \dfrac{5}{4}\).
  • Ordering negatives the wrong way: −0.5 is SMALLER than −0.35. On a number line, further left is smaller.
  • Ignoring the end of an inequality: \(<\) leaves the end value out; \(\leq\) puts it in.
5 How the exam asks this
  • Paper 2 (no calculator): “Write 360 as a product of its prime factors” [2] and “Find the HCF / LCM of …” [2–3] appear very often, sometimes with numbers given already in index form (Q3 style).
  • Word problems hide HCF/LCM: “largest tile”, “next time together”, “smallest number of packs”. Decide first whether you need the HCF (dividing up) or the LCM (meeting again).
  • Command words: “Write down” (1 mark, no working needed), “Find” or “Work out” (show steps), “Show that” (every step must be written).
  • Ordering questions are usually [2]: one mark for correct decimal conversions, one for the correct order in the original form.
  • Rational/irrational and reciprocal questions are short [1–2] items, but they feed directly into the surds unit (N-E6) on Paper 4.